2n^2-30n+112=0

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Solution for 2n^2-30n+112=0 equation: 



2n^2-30n+112=0

a = 2; b = -30; c = +112;
Δ = b2-4ac
Δ = -302-4·2·112
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2}{2*2}=\frac{28}{4}
=7
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2}{2*2}=\frac{32}{4}
=8
$

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